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Search: id:A079343
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| A079343 |
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F(n) mod 4, where F(n)=A000045(n) is the n-th Fibonacci number. |
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+0
9
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| 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1, 2, 3, 1, 0, 1, 1
(list; graph; listen)
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OFFSET
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0,4
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COMMENT
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Periodic with period of length 6 = (0,1,1,2,3,1). - Benoit Cloitre (benoit7848c(AT)orange.fr), Jan 05 2003
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FORMULA
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a(n)=(1/90)*{23*[n mod 6]+38*[(n+1) mod 6]-7*[(n+2) mod 6]-7*[(n+3) mod 6]+8*[(n+4) mod 6]-7*[(n+5) mod 6]}, with n>=0. - Paolo P. Lava (ppl(AT)spl.at), May 30 2007
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EXAMPLE
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a(6) = F(6) mod 4 = 8 mod 4 = 0.
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MATHEMATICA
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f[n_]:=Mod[Fibonacci[n], 4]; lst={}; Do[AppendTo[lst, f[n]], {n, 0, 6!}]; lst [From Vladimir Orlovsky (4vladimir(AT)gmail.com), Feb 18 2010]
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PROGRAM
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(PARI) for (n=0, 100, print1(fibonacci(n)%4", "))
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CROSSREFS
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Cf. A079344, A079345.
Sequence in context: A124314 A059087 A030373 this_sequence A004566 A050074 A006705
Adjacent sequences: A079340 A079341 A079342 this_sequence A079344 A079345 A079346
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KEYWORD
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nonn,new
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AUTHOR
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Jon Perry (perry(AT)globalnet.co.uk), Jan 04 2003
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