Search: id:A134986 Results 1-1 of 1 results found. %I A134986 %S A134986 2,3,2,3,4,5,5,6,7,8,9,10,10,11,12,13,14,15,16,17,17,18,19,20,21,22,23, %T A134986 24,25,26,26,27,28,29,30,31,32,33,34,35,36,37,37,38,39,40,41,42,43,44, %U A134986 45,46,47,48,49,50,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,65 %N A134986 a(n) = smallest integer m not equal to n such that n = (floor(n^2/m) + m)/2. %C A134986 This sequence complements A000037. - Alexander R. Povolotsky (pevnev(AT)juno.com), Feb 10 2008 %H A134986 Joshua Zucker (joshua.zucker(AT)stanfordalumni.org), Feb 23 2008, Table of n, a(n) for n = 1..200 %e A134986 a(1)=2 because (floor(1/2) + 2)/2 = 1 %e A134986 a(2)=3 because (floor(4/3) + 3)/2 = 2 %e A134986 a(3)=2 because (floor(9/2) + 2)/2 = 3 %e A134986 a(4)=3 because (floor(16/3)+ 3))/2 = 4 %e A134986 a(5)=4 because (floor(25/4)+ 4))/2 = 5 %e A134986 a(6)=5 because (floor(36/5)+ 5))/2 = 6 %e A134986 a(7)=5 because (floor(49/5)+ 5))/2 = 7 %Y A134986 Sequence in context: A083219 A106249 A110516 this_sequence A162751 A026342 A078198 %Y A134986 Adjacent sequences: A134983 A134984 A134985 this_sequence A134987 A134988 A134989 %K A134986 nonn %O A134986 1,1 %A A134986 Alexander R. Povolotsky (pevnev(AT)juno.com), Feb 05 2008; corrected Feb 07 2008 at the suggestion of Carl R. White (oeisfan(AT)phodd.net). %E A134986 More terms from Joshua Zucker (joshua.zucker(AT)stanfordalumni.org), Feb 23 2008 Search completed in 0.001 seconds